375 people were at the airport one friday night, and 78 of them were going to cleveland. what is the…

375 people were at the airport one friday night, and 78 of them were going to cleveland. what is the probability that a randomly selected passenger was flying to cleveland? write your answer as a fraction or whole number. p(cleveland) =

375 people were at the airport one friday night, and 78 of them were going to cleveland. what is the probability that a randomly selected passenger was flying to cleveland? write your answer as a fraction or whole number. p(cleveland) =

Answer

Explanation:

Step1: Recall probability formula

The probability formula is $P(A)=\frac{\text{Number of favorable outcomes}}{\text{Total number of outcomes}}$.

Step2: Identify values

The number of favorable outcomes (people going to Cleveland) is 78, and the total number of outcomes (total people at the airport) is 375. So, $P(\text{Cleveland})=\frac{78}{375}$.

Step3: Simplify fraction

Find the greatest - common divisor of 78 and 375. The GCD of 78 and 375 is 3. Divide both the numerator and denominator by 3: $\frac{78\div3}{375\div3}=\frac{26}{125}$.

Answer:

$\frac{26}{125}$