there are 50 red beans and 50 white beans in a bag. the first bean selected is red. the red bean is returned…

there are 50 red beans and 50 white beans in a bag. the first bean selected is red. the red bean is returned to the bag. what are the chances of the second bean selected being red?\na. $\frac{1}{49}$\nb. $\frac{1}{50}$\nc. $\frac{1}{100}$\nd. $\frac{49}{100}$\ne. $\frac{50}{100}$

there are 50 red beans and 50 white beans in a bag. the first bean selected is red. the red bean is returned to the bag. what are the chances of the second bean selected being red?\na. $\frac{1}{49}$\nb. $\frac{1}{50}$\nc. $\frac{1}{100}$\nd. $\frac{49}{100}$\ne. $\frac{50}{100}$

Answer

Explanation:

Step1: Calculate total number of beans

Since there are 50 red beans and 50 white beans, the total number of beans is $50 + 50=100$.

Step2: Determine probability of selecting red bean

The probability of an event is the number of favorable outcomes divided by the total number of outcomes. The number of favorable outcomes (selecting a red bean) is 50, and the total number of outcomes is 100. So the probability $P=\frac{50}{100}$.

Answer:

E. $\frac{50}{100}$