adam invested $24,000 in an account paying an interest rate of 2.8% compounded quarterly. assuming no…

adam invested $24,000 in an account paying an interest rate of 2.8% compounded quarterly. assuming no deposits or withdrawals are made, how much money, to the nearest ten dollars, would be in the account after 10 years?
Answer
Explanation:
Step1: Identify compound interest formula
The formula for compound interest is $A = P\left(1+\frac{r}{n}\right)^{nt}$, where:
- $A$ = final amount
- $P$ = principal amount
- $r$ = annual interest rate (decimal)
- $n$ = number of times interest is compounded per year
- $t$ = time in years
Step2: Convert values to correct format
$P = 24000$, $r = \frac{2.8}{100}=0.028$, $n=4$ (quarterly), $t=10$
Step3: Substitute values into formula
$A = 24000\left(1+\frac{0.028}{4}\right)^{4\times10}$ $A = 24000\left(1+0.007\right)^{40}$ $A = 24000\left(1.007\right)^{40}$
Step4: Calculate the exponential term
First compute $(1.007)^{40} \approx 1.322053$
Step5: Compute final amount
$A = 24000 \times 1.322053 \approx 31729.27$
Step6: Round to nearest ten dollars
Round $31729.27$ to the nearest ten: $31730$
Answer:
$$31,730$