aisha records the outdoor temperature, in degrees fahrenheit (°f), each day for 5 days in the table…

aisha records the outdoor temperature, in degrees fahrenheit (°f), each day for 5 days in the table shown.\noutdoor temperature\n| day | temperature (°f) |\n| monday | 76.5 |\n| tuesday | 70.2 |\n| wednesday | 63.0 |\n| thursday | 71.9 |\n| friday | 73.4 |\nwhat is the mean temperature of aishas data?

aisha records the outdoor temperature, in degrees fahrenheit (°f), each day for 5 days in the table shown.\noutdoor temperature\n| day | temperature (°f) |\n| monday | 76.5 |\n| tuesday | 70.2 |\n| wednesday | 63.0 |\n| thursday | 71.9 |\n| friday | 73.4 |\nwhat is the mean temperature of aishas data?

Answer

Answer:

71

Explanation:

Step1: Recall mean formula

The mean $\bar{x}=\frac{\sum_{i = 1}^{n}x_{i}}{n}$, where $n$ is the number of data - points and $x_{i}$ are the individual data - points. Here, $n = 5$, $x_1=76.5$, $x_2 = 70.2$, $x_3=63.0$, $x_4 = 71.9$, $x_5=73.4$.

Step2: Calculate sum of data

$\sum_{i = 1}^{5}x_{i}=76.5 + 70.2+63.0 + 71.9+73.4=355$

Step3: Calculate the mean

$\bar{x}=\frac{355}{5}=71$