alec attended his towns annual worm charming competition. contestants are assigned to a square foot of land…

alec attended his towns annual worm charming competition. contestants are assigned to a square foot of land, where they have 30 minutes to \charm\ worms to the surface of the dirt using a single technique. alec observed contestants charming techniques, and kept track of how many worms surfaced.\n| |tapping the ground|raking the ground|\n|----|----|----|\n|5 - 10 worms|6|5|\n|11 - 20 worms|5|8|\n|21 - 30 worms|10|4|\nwhat is the probability that a randomly selected contestant charmed 11 - 20 worms or 5 - 10 worms?\nsimplify any fractions.

alec attended his towns annual worm charming competition. contestants are assigned to a square foot of land, where they have 30 minutes to \charm\ worms to the surface of the dirt using a single technique. alec observed contestants charming techniques, and kept track of how many worms surfaced.\n| |tapping the ground|raking the ground|\n|----|----|----|\n|5 - 10 worms|6|5|\n|11 - 20 worms|5|8|\n|21 - 30 worms|10|4|\nwhat is the probability that a randomly selected contestant charmed 11 - 20 worms or 5 - 10 worms?\nsimplify any fractions.

Answer

Explanation:

Step1: Calculate total number of contestants

First, find the sum of all values in the table. $(6 + 5)+(5 + 8)+(10 + 4)=38$.

Step2: Calculate number of contestants who charmed 11 - 20 or 5 - 10 worms

Add the number of contestants in the 5 - 10 and 11 - 20 worm - ranges. $(6 + 5)+(5 + 8)=24$.

Step3: Calculate the probability

The probability $P$ is the number of favorable outcomes divided by the total number of outcomes. So $P=\frac{24}{38}=\frac{12}{19}$.

Answer:

$\frac{12}{19}$