among 320 randomly selected airline travelers, the mean number of hours spent travelling per year is 24…

among 320 randomly selected airline travelers, the mean number of hours spent travelling per year is 24 hours and the standard deviation is 2.9. what is the margin of error, assuming a 90% confidence level? round your answer to the nearest tenth. done

among 320 randomly selected airline travelers, the mean number of hours spent travelling per year is 24 hours and the standard deviation is 2.9. what is the margin of error, assuming a 90% confidence level? round your answer to the nearest tenth. done

Answer

Answer:

0.3

Explanation:

Step1: Identify the formula

Margin of error $E = z^*\frac{\sigma}{\sqrt{n}}$

Step2: Identify the values

$z^* = 1.645$ (from table for 90% confidence level), $\sigma=2.9$, $n = 320$

Step3: Calculate the margin of error

$E=1.645\times\frac{2.9}{\sqrt{320}}\approx1.645\times\frac{2.9}{17.89}\approx1.645\times0.162\approx 0.3$