andre measured the lengths of 10 sticks to the nearest inch. the lengths of the sticks were 3, 3, 4, 3, 3…

Explanation:

Step1: Count frequencies of each length

For length 3: count how many times 3 appears. The data is 3,3,4,3,3,5,4,6,5,4. So 3 appears 4 times.
For length 4: 4 appears 3 times (4,4,4? Wait, no: original data: 3,3,4,3,3,5,4,6,5,4. Let's list: 3 (4 times), 4 (3 times: positions 3,7,10), 5 (2 times: 6,9), 6 (1 time: 8). Wait, wait: let's count again. Data points: 3,3,4,3,3,5,4,6,5,4. So:

• 3: indices 1,2,4,5 → 4 times.
• 4: indices 3,7,10 → 3 times? Wait no: 3,3,4 (1), 3 (2), 3 (3), 5 (1), 4 (2), 6 (1), 5 (2), 4 (3). So 4 appears 3 times? Wait no, 3,3,4,3,3,5,4,6,5,4: that's 10 numbers. Let's count each:
• 3: 1,2,4,5 → 4 times.
• 4: 3,7,10? Wait 3 is first, 3 second, 4 third, 3 fourth, 3 fifth, 5 sixth, 4 seventh, 6 eighth, 5 ninth, 4 tenth. So 4: third, seventh, tenth → 3 times? Wait no, third, seventh, tenth: that's 3 times? Wait 3,3,4,3,3,5,4,6,5,4: 4 appears at positions 3,7,10 → three times? Wait 3,3,4 (1), 3 (2), 3 (3), 5 (1), 4 (2), 6 (1), 5 (2), 4 (3). So 4: 3 times? Wait 3,3,4,3,3,5,4,6,5,4: let's list counts:
• 3: 4 times (values: 3,3,3,3)
• 4: 3 times (values: 4,4,4)
• 5: 2 times (values: 5,5)
• 6: 1 time (value: 6)

Wait, no: 3 appears 4 times (1,2,4,5), 4 appears 3 times (3,7,10? Wait 3 is index 1, 3 index 2, 4 index 3, 3 index 4, 3 index 5, 5 index 6, 4 index 7, 6 index 8, 5 index 9, 4 index 10. So 4: indices 3,7,10 → three 4s? Wait 3,3,4,3,3,5,4,6,5,4: that's 10 numbers. Let's count:
3: 4 times (numbers 1,2,4,5: four 3s)
4: 3 times (numbers 3,7,10: three 4s? Wait 3,7,10: 3,7,10: three numbers? Wait 3 is first 4, 7 is second 4, 10 is third 4. So 3 times.
5: 2 times (numbers 6,9: two 5s)
6: 1 time (number 8: one 6)

Now, the line plots have Xs above each length (3,4,5,6). So:

• Above 3: 4 Xs (since 3 appears 4 times).
• Above 4: 3 Xs (since 4 appears 3 times).
• Above 5: 2 Xs (since 5 appears 2 times).
• Above 6: 1 X (since 6 appears 1 time).

Now check the four plots:

First plot:
3: 4 Xs? Wait first plot: 3 has 4 Xs? Wait first plot: 3: XXXX (4), 4: XXX (3)? Wait no, first plot: 3: XXXX (4), 4: XXX (3)? Wait no, looking at the first plot: 3 has 4 Xs (vertical), 4 has 3? Wait no, first plot: 3: XXXX (4), 4: XXX (3)? Wait no, first plot: 3: XXXX (4), 4: XXX (3)? Wait the first plot: 3: 4 Xs, 4: 3 Xs? Wait no, let's look at the four plots:

First plot:
3: XXXX (4)
4: XXX (3)? Wait no, first plot: 3: 4 Xs, 4: 3? Wait no, first plot: 3: 4 Xs, 4: 3 Xs, 5: 1 X, 6: 2 Xs? No, the first plot's 5 has 1 X, 6 has 2 Xs. But we need 5: 2 Xs, 6: 1 X. So first plot is wrong.

Second plot:
3: 4 Xs (XXXX), 4: 3 Xs (XXX), 5: 2 Xs (XX), 6: 1 X (X). Wait, second plot: 3: XXXX (4), 4: XXX (3), 5: XX (2), 6: X (1). Let's check:

3: 4 times → XXXX (4)
4: 3 times → XXX (3)
5: 2 times → XX (2)
6: 1 time → X (1)

Yes! So second plot matches: 3 has 4 Xs, 4 has 3, 5 has 2, 6 has 1.

Wait let's confirm the counts again:

Data: 3,3,4,3,3,5,4,6,5,4.

Count of 3: 4 (correct: 4 Xs)
Count of 4: 3 (correct: 3 Xs)
Count of 5: 2 (correct: 2 Xs)
Count of 6: 1 (correct: 1 X)

So the second plot (middle-left, second from left) is the correct one.

Answer: The second line plot (the one in the second position from the left)