anthony wants to know the average daily high temperatures in his town during the summer. he chose two random…

anthony wants to know the average daily high temperatures in his town during the summer. he chose two random samples of 10 consecutive days and recorded the daily high temperatures. the daily high temperatures in fahrenheit are as follows. sample 1: 78 82 85 87 90 85 79 86 91 88 sample 2: 81 79 80 86 89 92 82 88 84 87 find the mean daily high temperatures of each sample and calculate the difference between these mean daily high temperatures. express your answer as a decimal rounded to the nearest tenth. (2 points) the mean daily high temperature of sample 1 is . the mean daily high temperature of sample 2 is . the mean daily high temperatures of the two samples differ by .
Answer
Explanation:
Step1: Calculate mean of Sample 1
The formula for the mean $\bar{x}=\frac{\sum_{i = 1}^{n}x_{i}}{n}$. For Sample 1, $n = 10$, and $\sum_{i=1}^{10}x_{i}=78 + 82+85 + 87+90+85+79+86+91+88=841$. So, $\bar{x}_1=\frac{841}{10}=84.1$.
Step2: Calculate mean of Sample 2
For Sample 2, $n = 10$, and $\sum_{i = 1}^{10}x_{i}=81+79+80+86+89+92+82+88+84+87 = 848$. So, $\bar{x}_2=\frac{848}{10}=84.8$.
Step3: Calculate the difference
The difference $d=\vert\bar{x}_1-\bar{x}_2\vert=\vert84.1 - 84.8\vert= 0.7$.
Answer:
The mean daily high temperature of Sample 1 is $84.1$. The mean daily high temperature of Sample 2 is $84.8$. The mean daily high temperatures of the two samples differ by $0.7$.