assume a normal distribution of scores has a mean of 52 and a standard deviation of 4. what is the range of…

assume a normal distribution of scores has a mean of 52 and a standard deviation of 4. what is the range of the middle 95% of the distribution?\no 48 - 56\no 44 - 60\no 40 - 64\no 48 - 60
Answer
Explanation:
Step1: Recall the property of normal distribution
For a normal distribution, the middle 95% of the data lies within 2 standard - deviations of the mean.
Step2: Calculate the lower bound
The lower bound is $\mu - 2\sigma$, where $\mu = 52$ and $\sigma = 4$. So, $52-2\times4=52 - 8 = 44$.
Step3: Calculate the upper bound
The upper bound is $\mu + 2\sigma$, where $\mu = 52$ and $\sigma = 4$. So, $52 + 2\times4=52+8 = 60$.
Answer:
44 - 60