the average january surface water temperatures (°c) of lake michigan from 2000 to 2009 were 5.07, 3.57…

the average january surface water temperatures (°c) of lake michigan from 2000 to 2009 were 5.07, 3.57, 5.32, 3.19, 3.49, 4.25, 4.76, 5.19, 3.94, and 4.34. the mean value of these temperatures is 4.312. what is the variance of this data set?

the average january surface water temperatures (°c) of lake michigan from 2000 to 2009 were 5.07, 3.57, 5.32, 3.19, 3.49, 4.25, 4.76, 5.19, 3.94, and 4.34. the mean value of these temperatures is 4.312. what is the variance of this data set?

Answer

Explanation:

Step1: Recall variance formula

The formula for the variance $s^{2}$ of a sample is $s^{2}=\frac{\sum_{i = 1}^{n}(x_{i}-\bar{x})^{2}}{n - 1}$, where $n$ is the number of data - points, $x_{i}$ are the individual data - points, and $\bar{x}$ is the mean. Here, $n = 10$.

Step2: Sum the squared differences

From the table, $\sum_{i=1}^{10}(x_{i}-\bar{x})^{2}=0.575 + 0.551+1.016 + 1.259+0.676+0.004+0.201+0.771+0.138+0.001=5.192$.

Step3: Calculate the variance

Using the formula $s^{2}=\frac{\sum_{i = 1}^{n}(x_{i}-\bar{x})^{2}}{n - 1}$, substitute $n = 10$ and $\sum_{i=1}^{n}(x_{i}-\bar{x})^{2}=5.192$. Then $s^{2}=\frac{5.192}{10 - 1}=\frac{5.192}{9}\approx0.577$.

Answer:

$0.577$