a bag has 2 blue marbles, 3 red marbles, and 5 white marbles. which events have a probability greater than…

Explanation:

Step1: Calculate total number of marbles

$2 + 3+5=10$

Step2: Calculate probability of choosing 1 blue marble

$P(\text{blue})=\frac{2}{10}=\frac{1}{5}$

Step3: Calculate probability of choosing 1 red marble

$P(\text{red})=\frac{3}{10}$ Since $\frac{3}{10}>\frac{1}{5}$

Step4: Calculate probability of choosing 1 red then 1 blue (without - replacement)

$P(\text{red then blue})=\frac{3}{10}\times\frac{2}{9}=\frac{6}{90}=\frac{1}{15}$ Since $\frac{1}{15}<\frac{1}{5}$

Step5: Calculate probability of choosing 1 white, replacing and then another white

$P(\text{white then white})=\frac{5}{10}\times\frac{5}{10}=\frac{25}{100}=\frac{1}{4}$ Since $\frac{1}{4}>\frac{1}{5}$

Step6: Calculate probability of choosing 1 white marble

$P(\text{white})=\frac{5}{10}=\frac{1}{2}$ Since $\frac{1}{2}>\frac{1}{5}$

Answer:

B. choosing 1 red marble D. choosing 1 white marble, replacing it, and choosing another white marble E. choosing 1 white marble