a bag contains 42 red, 45 green, 20 yellow, and 32 purple candy. you pick one candy at random. find the…

a bag contains 42 red, 45 green, 20 yellow, and 32 purple candy. you pick one candy at random. find the probability that it is green or yellow. p(green or yellow) = ?

a bag contains 42 red, 45 green, 20 yellow, and 32 purple candy. you pick one candy at random. find the probability that it is green or yellow. p(green or yellow) = ?

Answer

Explanation:

Step1: Calculate total number of candies

$42 + 45+20 + 32=139$

Step2: Calculate number of green or yellow candies

$45 + 20=65$

Step3: Calculate the probability

$P(\text{green or yellow})=\frac{65}{139}$

Answer:

$\frac{65}{139}$