a bag contains 42 red, 45 green, 20 yellow, and 32 purple candy. you pick one candy at random. find the…

a bag contains 42 red, 45 green, 20 yellow, and 32 purple candy. you pick one candy at random. find the probability that it is green or yellow. p(green or yellow) = \\frac{?}{} simplify your answer completely.

a bag contains 42 red, 45 green, 20 yellow, and 32 purple candy. you pick one candy at random. find the probability that it is green or yellow. p(green or yellow) = \\frac{?}{} simplify your answer completely.

Answer

Explanation:

Step1: Calculate the total number of candies

The total number of candies is the sum of red, green, yellow, and purple candies. $$42 + 45+20 + 32=139$$

Step2: Calculate the number of green or yellow candies

The number of green or yellow candies is (45 + 20=65)

Step3: Calculate the probability

The probability (P(\text{green or yellow})) is the number of green or yellow candies divided by the total number of candies. $$P(\text{green or yellow})=\frac{65}{139}$$

Answer:

(\frac{65}{139})