a bag contains eleven equally sized marbles, which are numbered. two marbles are chosen at random and…

Answer:

B. $\frac{24}{121}$

Explanation:

Step 1: Determine number of shaded marbles and odd-numbered marbles

Shaded marbles: 4 (1, 3, 4, 9), odd-numbered marbles: 6 (1, 3, 5, 7, 9, 11).

Step 2: Calculate probability of first event (shaded marble)

Probability = $\frac{\text{Number of shaded marbles}}{\text{Total marbles}} = \frac{4}{11}$.

Step 3: Calculate probability of second event (odd-numbered marble)

Probability = $\frac{\text{Number of odd-numbered marbles}}{\text{Total marbles}} = \frac{6}{11}$.

Step 4: Multiply probabilities for independent events

Combined probability = $\frac{4}{11} \times \frac{6}{11} = \frac{24}{121}$.