a bag contains 4 red marbles, 2 blue marbles and 3 green marbles. if two marbles are drawn out of the bag…

Explanation:

Step1: Calculate total marbles

$4 + 2+3=9$ marbles initially.

Step2: Calculate probability of first - blue marble

The probability of drawing the first blue marble is $\frac{2}{9}$ since there are 2 blue marbles out of 9 total marbles.

Step3: Calculate probability of second - blue marble

After drawing one blue marble, there is 1 blue marble left and 8 total marbles left. So the probability of drawing the second blue marble is $\frac{1}{8}$.

Step4: Calculate probability of both events

Since these are dependent events, we multiply the probabilities of each event. So the probability that both marbles are blue is $\frac{2}{9}\times\frac{1}{8}=\frac{2}{72}=\frac{1}{36}$.

Answer:

$\frac{1}{36}$