a bag contains 7 red marbles, 4 blue marbles and 6 green marbles. if two marbles are drawn out of the bag…

Explanation:

Step1: Calculate total number of marbles

Total marbles = 7 + 4+ 6 = 17

Step2: Calculate probability of first - blue marble

Probability of first blue marble = $\frac{4}{17}$

Step3: Calculate probability of second - blue marble

Since no replacement, there are 3 blue marbles left and 16 total marbles left. Probability of second blue marble = $\frac{3}{16}$

Step4: Calculate probability of both blue marbles

By multiplication rule of probability for dependent events, probability of both blue = $\frac{4}{17}\times\frac{3}{16}=\frac{12}{272}\approx0.044$

Answer:

0.044