a bag contains 5 red marbles, 6 blue marbles and 2 green marbles. if two marbles are drawn out of the bag…

a bag contains 5 red marbles, 6 blue marbles and 2 green marbles. if two marbles are drawn out of the bag (without replacement), what is the probability, to the nearest 1000th, that both marbles drawn will be red?

a bag contains 5 red marbles, 6 blue marbles and 2 green marbles. if two marbles are drawn out of the bag (without replacement), what is the probability, to the nearest 1000th, that both marbles drawn will be red?

Answer

Explanation:

Step1: Calculate total marbles

The total number of marbles initially is $5 + 6+2=13$.

Step2: Calculate first - red marble probability

The probability of drawing a red marble on the first draw is $\frac{5}{13}$ since there are 5 red marbles out of 13 total marbles.

Step3: Calculate second - red marble probability

After drawing one red marble, there are 4 red marbles left and 12 total marbles left. So the probability of drawing a red marble on the second draw is $\frac{4}{12}$.

Step4: Calculate probability of both red

The probability of both events happening (drawing two red marbles) is the product of the probabilities of each event. So $P=\frac{5}{13}\times\frac{4}{12}=\frac{20}{156}\approx 0.128$.

Answer:

$0.128$