a bag contains 8 red marbles, 2 blue marbles and 4 green marbles. if two marbles are drawn out of the bag…

Explanation:

Step1: Calculate total marbles

$8 + 2+4=14$ marbles

Step2: Calculate first - red marble probability

The probability of drawing a red marble first is $\frac{8}{14}$.

Step3: Calculate second - red marble probability

Since there is no replacement, for the second draw, there are 7 red marbles left and 13 marbles in total. So the probability is $\frac{7}{13}$.

Step4: Calculate combined probability

The probability that both are red is $\frac{8}{14}\times\frac{7}{13}=\frac{8\times7}{14\times13}=\frac{56}{182}\approx 0.3077$.

Step5: Convert to percentage

$0.3077\times100 = 30.77%$. Rounding to the nearest tenth of a percent gives $30.8%$.

Answer:

$30.8%$