a bag contains 1 red, 1 yellow, 1 blue, and 1 green marble. what is the probability of choosing a green…

a bag contains 1 red, 1 yellow, 1 blue, and 1 green marble. what is the probability of choosing a green marble, not replacing it, and then choosing a red marble?\n$\frac{1}{16}$\n$\frac{1}{12}$\n$\frac{1}{4}$\n$\frac{1}{2}$

a bag contains 1 red, 1 yellow, 1 blue, and 1 green marble. what is the probability of choosing a green marble, not replacing it, and then choosing a red marble?\n$\frac{1}{16}$\n$\frac{1}{12}$\n$\frac{1}{4}$\n$\frac{1}{2}$

Answer

Explanation:

Step1: Probability of green marble

Total marbles = 4, green marbles = 1. $P(\text{green}) = \frac{1}{4}$

Step2: Probability of red marble (no replacement)

Remaining marbles = 3, red marbles = 1. $P(\text{red after green}) = \frac{1}{3}$

Step3: Multiply the two probabilities

$P(\text{green then red}) = \frac{1}{4} \times \frac{1}{3}$

Answer:

$\frac{1}{12}$ (Option B. $\frac{1}{12}$)