a bag has 5 yellow marbles, 4 blue marbles, 7 green marbles, and 4 red marbles. what is the probability of…

a bag has 5 yellow marbles, 4 blue marbles, 7 green marbles, and 4 red marbles. what is the probability of picking a yellow marble from the bag with replacement twice?\n$\frac{1}{5}$\n$\frac{1}{25}$\n$\frac{1}{16}$\n$\frac{1}{8}$
Answer
Explanation:
Step1: Calculate total marbles
$5 + 4+7 + 4=20$
Step2: Calculate probability of picking yellow once
The probability of picking a yellow marble once is $\frac{5}{20}=\frac{1}{4}$ since there are 5 yellow marbles out of 20 total marbles.
Step3: Calculate probability of picking yellow twice with replacement
Since the events are independent (because of replacement), the probability of picking a yellow marble twice is $\frac{1}{4}\times\frac{1}{4}=\frac{1}{16}$
Answer:
$\frac{1}{16}$