bart found 20 quadrilaterals in his classroom. he made a venn diagram using the properties of the…

Answer:

33%

Explanation:

Step1: Identify relevant values

The number of quadrilaterals with four right - angles is (6 + 2=8). The number of quadrilaterals with four right - angles and four equal side lengths is (2).

Step2: Use conditional probability formula

The formula for conditional probability (P(A|B)=\frac{P(A\cap B)}{P(B)}). In the context of counting, if (A) is the event of having four equal side lengths and (B) is the event of having four right - angles, then (P(A|B)=\frac{n(A\cap B)}{n(B)}), where (n(A\cap B)) is the number of elements in (A\cap B) and (n(B)) is the number of elements in (B). So (P=\frac{2}{8}=0.25).

Step3: Convert to percentage

(0.25\times100% = 25%) (This is wrong above, correct as follows)

The number of quadrilaterals with four right - angles is (6 + 2=8). The number of quadrilaterals with four right - angles and four equal side lengths is (2). The probability (P=\frac{2}{6 + 2}=\frac{2}{8}=0.25) (wrong). The correct way: The number of quadrilaterals with four right - angles is (6+2 = 8). The number of quadrilaterals with four right - angles and four equal side lengths is (2). The probability (P=\frac{2}{6 + 2}=\frac{2}{8}=0.25) (wrong). We want (P(\text{four equal sides}|\text{four right angles})). The number of quadrilaterals with four right angles is (6 + 2=8). The number of quadrilaterals with both four right angles and four equal side lengths is (2). The probability (P=\frac{2}{8}=0.25) (wrong). The number of quadrilaterals with four right angles is (6+2 = 8). The number of quadrilaterals with four right angles and four equal side lengths is (2). The correct probability: The number of quadrilaterals with four right angles (n(R)=6 + 2=8). 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