basic probability review worksheet - fall 2025\na 6 - sided die is rolled one time. find:\n1. p(roll a…

basic probability review worksheet - fall 2025\na 6 - sided die is rolled one time. find:\n1. p(roll a 5)\n2. p(roll a 1 or 6)\n3. p(odd #)\n4. p(multiple of 3)\n5. p(not a 4)\n\na card is drawn from a standard 52 - card deck. find:\n6. p(ace)\n7. p(red)\n8. p(diamond)\n9. p(face)\n10. p(2 or 3)\n11. p(black or heart)\n12. p(not a king)\n13. p(not a face)\n\nthere are 6 red, 3 blue, and 1 white marbles in a jar. find:\n14. p(blue)\n15. p(red or white)\n16. p(green)\n17. p(non - white)\n18. p(non - yellow)\n\na random number from 1 to 20 is drawn from a hat. find:\n19. p(7)\n20. p(6 or lower)\n21. p(18 or higher)\n22. p(multiple of 4)\n23. p(9 or 11)\n24. p(not a 15)\n25. p(21)
Answer
Explanation:
Step1: Recall probability formula
The probability formula is $P(A)=\frac{n(A)}{n(S)}$, where $n(A)$ is the number of favorable outcomes and $n(S)$ is the total number of outcomes.
Step2: Solve for P(7) (Question 19)
There is 1 favorable outcome (the number 7) and 20 total outcomes (numbers from 1 - 20). So $P(7)=\frac{1}{20}$.
Step3: Solve for P(6 or lower) (Question 20)
The favorable outcomes are 1, 2, 3, 4, 5, 6. So $n(A) = 6$ and $n(S)=20$. Then $P(6\text{ or lower})=\frac{6}{20}=\frac{3}{10}$.
Step4: Solve for P(18 or higher) (Question 21)
The favorable outcomes are 18, 19, 20. So $n(A)=3$ and $n(S) = 20$. Then $P(18\text{ or higher})=\frac{3}{20}$.
Step5: Solve for P(multiple of 4) (Question 22)
The multiples of 4 from 1 - 20 are 4, 8, 12, 16, 20. So $n(A)=5$ and $n(S)=20$. Then $P(\text{multiple of }4)=\frac{5}{20}=\frac{1}{4}$.
Step6: Solve for P(9 or 11) (Question 23)
There are 2 favorable outcomes (9 and 11) and 20 total outcomes. So $P(9\text{ or }11)=\frac{2}{20}=\frac{1}{10}$.
Step7: Solve for P(not a 15) (Question 24)
The number of non - 15 outcomes is $20 - 1=19$. So $P(\text{not a }15)=\frac{19}{20}$.
Step8: Solve for P(21) (Question 25)
There are 0 favorable outcomes (21 is not in the range 1 - 20) and 20 total outcomes. So $P(21)=0$.
Answer:
- $\frac{1}{20}$
- $\frac{3}{10}$
- $\frac{3}{20}$
- $\frac{1}{4}$
- $\frac{1}{10}$
- $\frac{19}{20}$
- $0$