bridge to mathematics. math 003 fall 2025\nhomework: unit 4 - mean, median and mode, and probability\nquestio…

bridge to mathematics. math 003 fall 2025\nhomework: unit 4 - mean, median and mode, and probability\nquestion list\nquestion 7\nquestion 8\nquestion 9\nquestion 10\nquestion 11\nquestion 12\nquestion 13\nquestion 13, 7.3.23\nhw score: 41.3%, 19 of 46 points\npoints: 0 of 1\nin a mathematics class, the following test scores were recorded for a student. find the median.\n81, 90, 86, 69, 72, 80\nthe median is (round to one decimal place as needed.)

bridge to mathematics. math 003 fall 2025\nhomework: unit 4 - mean, median and mode, and probability\nquestion list\nquestion 7\nquestion 8\nquestion 9\nquestion 10\nquestion 11\nquestion 12\nquestion 13\nquestion 13, 7.3.23\nhw score: 41.3%, 19 of 46 points\npoints: 0 of 1\nin a mathematics class, the following test scores were recorded for a student. find the median.\n81, 90, 86, 69, 72, 80\nthe median is (round to one decimal place as needed.)

Answer

Explanation:

Step1: Arrange scores in ascending order

$69,72,80,81,86,90$

Step2: Determine position of median

Since there are $n = 6$ (an even - numbered data set), the median is the average of the $\frac{n}{2}$th and $(\frac{n}{2}+ 1)$th ordered values. $\frac{n}{2}=\frac{6}{2}=3$ and $\frac{n}{2}+1 = 4$.

Step3: Calculate the median

The 3rd value is $80$ and the 4th value is $81$. Median $=\frac{80 + 81}{2}=\frac{161}{2}=80.5$

Answer:

$80.5$