bruno will spin the arrow on the spinner 2 times. what is the probability that the arrow will stop on c at…

bruno will spin the arrow on the spinner 2 times. what is the probability that the arrow will stop on c at least once?\n○ $\frac{1}{9}$\n○ $\frac{2}{9}$\n○ $\frac{1}{3}$\n○ $\frac{5}{9}$

bruno will spin the arrow on the spinner 2 times. what is the probability that the arrow will stop on c at least once?\n○ $\frac{1}{9}$\n○ $\frac{2}{9}$\n○ $\frac{1}{3}$\n○ $\frac{5}{9}$

Answer

Explanation:

Step1: Calculate non - C probability

The probability of not landing on C in one spin is $\frac{2}{3}$ since there are 2 non - C sections out of 3 total sections.

Step2: Calculate probability of no C in two spins

Since the spins are independent events, the probability of not landing on C in two spins is $\frac{2}{3}\times\frac{2}{3}=\frac{4}{9}$ by the multiplication rule for independent events.

Step3: Calculate probability of at least one C

The probability of at least one C is the complement of the probability of no C. So it is $1 - \frac{4}{9}=\frac{5}{9}$.

Answer:

$\frac{5}{9}$