calculate the probability of drawing a: blue card, then drawing another blue card, with no replacement…

Answer:

$\frac{1}{15}$

Explanation:

Step1: Count total and blue cards

There are 10 cards in total, 3 blue cards.

Step2: Probability of first - draw

The probability of drawing a blue card first is $\frac{3}{10}$.

Step3: Probability of second - draw

After drawing one blue card without replacement, there are 9 cards left and 2 blue cards left. So the probability of drawing a blue card second is $\frac{2}{9}$.

Step4: Calculate combined probability

The probability of both events is $\frac{3}{10}\times\frac{2}{9}=\frac{6}{90}=\frac{1}{15}$.