calculate the probability of drawing a blue, followed by a red marble. no replacement. what is the…

calculate the probability of drawing a blue, followed by a red marble. no replacement. what is the probability of drawing a red marble? $\frac{1}{10} \times \frac{2}{?} = \frac{2}{} =$

calculate the probability of drawing a blue, followed by a red marble. no replacement. what is the probability of drawing a red marble? $\frac{1}{10} \times \frac{2}{?} = \frac{2}{} =$

Answer

Explanation:

Step1: Determine total marbles after first draw

Since there is no - replacement, after drawing a blue marble (1 out of 10 initially), there are 9 marbles left.

Step2: Calculate probability of second - draw

The probability of drawing a red marble on the second draw is $\frac{2}{9}$ because there are 2 red marbles out of the remaining 9 marbles.

Step3: Calculate combined probability

The combined probability of drawing a blue marble first and then a red marble is $\frac{1}{10}\times\frac{2}{9}=\frac{2}{90}=\frac{1}{45}$.

Answer:

$\frac{1}{45}$