calculate the probability of drawing a: green card, then drawing a blue card, with no replacement. answer as…
calculate the probability of drawing a: green card, then drawing a blue card, with no replacement. answer as a fraction in lowest terms. enter the denominator. 1 ?
Answer
Explanation:
Step1: Calculate probability of green - card first
There are 5 green cards out of 10 cards initially. So the probability of drawing a green card first, $P(G_1)=\frac{5}{10}$.
Step2: Calculate probability of blue - card second
After drawing a green card (no replacement), there are 9 cards left and 3 blue cards. So the probability of drawing a blue card second given a green card was drawn first, $P(B_2|G_1)=\frac{3}{9}$.
Step3: Calculate joint probability
By the multiplication rule for dependent events $P(G_1\cap B_2)=P(G_1)\times P(B_2|G_1)=\frac{5}{10}\times\frac{3}{9}=\frac{15}{90}=\frac{1}{6}$.
Answer:
6