a candy is randomly drawn from a box with 6 chocolates, 13 candy canes, and 11 lollipops. event a: lollipop…

a candy is randomly drawn from a box with 6 chocolates, 13 candy canes, and 11 lollipops. event a: lollipop event b: candy cane p(a or b) = ? hint: p(a or b) = p(a) + p(b) round your answer to the nearest hundredth.
Answer
Explanation:
Step1: Calculate total number of candies
$6 + 13+11=30$
Step2: Calculate P(A)
$P(A)=\frac{11}{30}$
Step3: Calculate P(B)
$P(B)=\frac{13}{30}$
Step4: Calculate P(A or B)
$P(A\ or\ B)=P(A)+P(B)=\frac{11}{30}+\frac{13}{30}=\frac{11 + 13}{30}=\frac{24}{30}=0.80$
Answer:
$0.80$