center, spread, and shape of distributions: medium\nstudents at schools in different states calculated the…

center, spread, and shape of distributions: medium\nstudents at schools in different states calculated the volume of snow that it took to fill one cup of water after the snow had melted. their results, in cups, were: 3.7, 3.0, 3.9, 2.5, 2.5, 2.2\nto the nearest tenth of a cup, how much greater was the mean than the median of their calculations?\nshow calculator\nhow do i enter a student - produced response on the sat? show me\nreport a problem

center, spread, and shape of distributions: medium\nstudents at schools in different states calculated the volume of snow that it took to fill one cup of water after the snow had melted. their results, in cups, were: 3.7, 3.0, 3.9, 2.5, 2.5, 2.2\nto the nearest tenth of a cup, how much greater was the mean than the median of their calculations?\nshow calculator\nhow do i enter a student - produced response on the sat? show me\nreport a problem

Answer

Explanation:

Step1: Calculate the mean

The mean $\bar{x}=\frac{3.7 + 3.0+3.9+2.5+2.5+2.2}{6}=\frac{17.8}{6}\approx2.97$.

Step2: Arrange data in ascending - order

$2.2,2.5,2.5,3.0,3.7,3.9$.

Step3: Calculate the median

Since there are 6 data points, the median is the average of the 3rd and 4th ordered values. Median $=\frac{2.5 + 3.0}{2}=2.75$.

Step4: Find the difference

The difference between the mean and the median is $2.97-2.75 = 0.22\approx0.2$.

Answer:

$0.2$