in a certain algebra 2 class of 26 students, 8 of them play basketball and 9 of them play baseball. there…

in a certain algebra 2 class of 26 students, 8 of them play basketball and 9 of them play baseball. there are 12 students who play neither sport. what is the probability that a student chosen randomly from the class plays basketball or baseball?

in a certain algebra 2 class of 26 students, 8 of them play basketball and 9 of them play baseball. there are 12 students who play neither sport. what is the probability that a student chosen randomly from the class plays basketball or baseball?

Answer

Explanation:

Step1: Find number of students who play either sport

Total students = 26, students who play neither = 12. So number of students who play either sport is $26 - 12=14$.

Step2: Calculate probability

Probability = $\frac{\text{Number of favorable outcomes}}{\text{Total number of outcomes}}$. Number of favorable outcomes (students who play either sport) is 14, total number of students is 26. So probability is $\frac{14}{26}=\frac{7}{13}$.

Answer:

$\frac{7}{13}$