in a certain algebra 2 class of 30 students, 11 of them play basketball and 13 of them play baseball. there…

in a certain algebra 2 class of 30 students, 11 of them play basketball and 13 of them play baseball. there are 10 students who play neither sport. what is the probability that a student chosen randomly from the class plays basketball or baseball?

in a certain algebra 2 class of 30 students, 11 of them play basketball and 13 of them play baseball. there are 10 students who play neither sport. what is the probability that a student chosen randomly from the class plays basketball or baseball?

Answer

Explanation:

Step1: Find number of students who play either sport

Total students = 30, students who play neither = 10. So number of students who play either sport is $30 - 10=20$.

Step2: Calculate the probability

Probability = $\frac{\text{Number of favorable outcomes}}{\text{Total number of outcomes}}$. Here, favorable outcomes are students who play basketball or baseball (20) and total number of students is 30. So probability is $\frac{20}{30}=\frac{2}{3}$.

Answer:

$\frac{2}{3}$