in a certain algebra 2 class of 30 students, 18 of them play basketball and 16 of them play baseball. there…

in a certain algebra 2 class of 30 students, 18 of them play basketball and 16 of them play baseball. there are 8 students who play neither sport. what is the probability that a student chosen randomly from the class plays basketball or baseball?

in a certain algebra 2 class of 30 students, 18 of them play basketball and 16 of them play baseball. there are 8 students who play neither sport. what is the probability that a student chosen randomly from the class plays basketball or baseball?

Answer

Explanation:

Step1: Find number of students who play either sport

Total students = 30, students who play neither = 8. So number of students who play either sport is $30 - 8=22$.

Step2: Calculate the probability

Probability = $\frac{\text{Number of favorable outcomes}}{\text{Total number of outcomes}}$. Favorable outcomes (students who play basketball or baseball) is 22, total number of students is 30. So probability is $\frac{22}{30}=\frac{11}{15}$.

Answer:

$\frac{11}{15}$