for a certain class, the following data table summarizes the amount of sleep of students and whether or not…

for a certain class, the following data table summarizes the amount of sleep of students and whether or not they have an a in the class. what is the probability that a student chosen randomly from the class has an a?

for a certain class, the following data table summarizes the amount of sleep of students and whether or not they have an a in the class. what is the probability that a student chosen randomly from the class has an a?

Answer

Explanation:

Step1: Calculate total number of students

Add all values in the table: (5 + 3+7 + 13). [5+3 + 7+13=(5 + 3)+(7 + 13)=8 + 20=28]

Step2: Calculate number of students with an A

Add the values in the "Has an A" row: (5+3). [5 + 3=8]

Step3: Calculate the probability

Use the formula (P=\frac{\text{Number of favorable outcomes}}{\text{Total number of outcomes}}). Here, the number of favorable outcomes (students with an A) is (8), and the total number of outcomes (total students) is (28). So (P=\frac{8}{28}). Simplify the fraction by dividing numerator and denominator by (4): (\frac{8\div4}{28\div4}=\frac{2}{7}).

Answer:

(\frac{2}{7})