in a certain orchard, the number of apples (a) on a tree is normally distributed with a mean of 300 apples…

in a certain orchard, the number of apples (a) on a tree is normally distributed with a mean of 300 apples and a standard deviation of 30 apples. find the probability that a given tree has between 240 and 300 apples.\n99.7%\n95%\n68%\n210 240 270 300 330 360 390\np(240 < a < 300) = ?%\nbe sure to use the 68% - 95% - 99.7% rule and do not round.
Answer
Explanation:
Step1: Recall the 68 - 95 - 99.7 rule
The 68 - 95 - 99.7 rule for a normal distribution states that about 68% of the data lies within 1 standard - deviation of the mean ($\mu\pm\sigma$), about 95% lies within 2 standard - deviations of the mean ($\mu\pm2\sigma$), and about 99.7% lies within 3 standard - deviations of the mean ($\mu\pm3\sigma$). Here, $\mu = 300$ and $\sigma=30$.
Step2: Determine the number of standard - deviations from the mean
The value 240 is $\frac{300 - 240}{30}=2$ standard - deviations below the mean ($\mu - 2\sigma$), and 300 is the mean ($\mu$).
Step3: Use the symmetry of the normal distribution
Since the normal distribution is symmetric about the mean, the percentage of data between $\mu - 2\sigma$ and $\mu$ is half of the percentage of data between $\mu - 2\sigma$ and $\mu + 2\sigma$. The percentage of data between $\mu - 2\sigma$ and $\mu+2\sigma$ is 95%. So the percentage of data between $\mu - 2\sigma$ and $\mu$ is $\frac{95%}{2}=47.5%$.
Answer:
47.5%