ch 12* choose an american household at random, and let the random variable x be the number of cars…

ch 12* choose an american household at random, and let the random variable x be the number of cars (including suvs and light trucks) the residents own. here is the probability model if we ignore the few households that own more than six cars\n\n|number of cars x|0|1|2|3|4|5|6|\n|--|--|--|--|--|--|--|--|\n|probability|0.09|0.33|0.36|0.14|0.05|0.02|0.01|\n\na housing company builds houses with two - car garages. what percent of households can be accommodated in the houses they built?\n\n33%\n22%\n36%\n78%

ch 12* choose an american household at random, and let the random variable x be the number of cars (including suvs and light trucks) the residents own. here is the probability model if we ignore the few households that own more than six cars\n\n|number of cars x|0|1|2|3|4|5|6|\n|--|--|--|--|--|--|--|--|\n|probability|0.09|0.33|0.36|0.14|0.05|0.02|0.01|\n\na housing company builds houses with two - car garages. what percent of households can be accommodated in the houses they built?\n\n33%\n22%\n36%\n78%

Answer

Explanation:

Step1: Identify relevant probabilities

We need to find the probability of households having 0, 1, or 2 cars since the houses have two - car garages. The probabilities for 0, 1, and 2 cars are 0.09, 0.33, and 0.36 respectively.

Step2: Calculate the total probability

We sum up the relevant probabilities: $P(X\leq2)=0.09 + 0.33+0.36$. $0.09 + 0.33+0.36=0.78$.

Step3: Convert to percentage

To convert the decimal to a percentage, we multiply by 100. $0.78\times100 = 78%$.

Answer:

78%