ch 12* here is the probability model for the political affiliation of a randomly chosen adult in the united…

ch 12* here is the probability model for the political affiliation of a randomly chosen adult in the united states.\npolitical affiliation republican independent democrat other\nprobability 0.25 0.42 0.30?\nthe probability that a randomly chosen american adults political affiliation is \other\ must be\nany number between 0 and 1.\n0.00.\n0.30.\n0.03.\nquestion 12 1 pts\nch 12 a candy company manufactures bags of colorful candies. the company reports that it makes 10% each of green and red candies and 20% each of yellow, blue, and orange candies. the rest of the candies are brown.\nif you pick a candy at random, what is the probability that it is brown?\n0.40\n0.10\n0.20\n0.30
Answer
Explanation:
Step1: Recall probability rule
The sum of probabilities of all possible outcomes in a probability - model is 1.
Step2: Calculate probability of 'Other' for political affiliation
Let (P(\text{Other})) be the probability of the 'Other' political affiliation. We know that (P(\text{Republican}) = 0.25), (P(\text{Independent})=0.42), (P(\text{Democrat}) = 0.30). Then (P(\text{Other})=1-(0.25 + 0.42+0.30)=1 - 0.97 = 0.03).
Step3: Calculate probability of brown candy
Let (P(\text{Brown})) be the probability of picking a brown candy. We know that (P(\text{Green})=0.10), (P(\text{Red}) = 0.10), (P(\text{Yellow})=0.20), (P(\text{Blue}) = 0.20), (P(\text{Orange})=0.20). Then (P(\text{Brown})=1-(0.10 + 0.10+0.20 + 0.20+0.20)=1 - 0.80=0.20).
Answer:
For the political - affiliation problem: 0.03 For the candy - color problem: 0.20