ch 15 an srs of 25 recent birth records at the local hospital was selected. in the sample, the average birth…

ch 15 an srs of 25 recent birth records at the local hospital was selected. in the sample, the average birth weight was $\bar{x}=119.6$ ounces. suppose the standard deviation is known to be $sigma = 6.5$ ounces. assume that in the population of all babies born in this hospital, the birth weights follow a normal distribution, with mean $mu$. the standard deviation of the sampling distribution of the mean is\n6.52 ounces.\n1.30 ounces.\n0.02 ounce.\n0.38 ounce.\n\nquestion 14\nch 15 suppose youre in a class of 35 students. the instructor takes a simple random sample of seven students and observes their heights. imagine all of the different samples possible. let x denote the tallest height in your sample. the distribution of all values taken by x in all possible samples of seven students selected from the 35 students in your class is\nthe sampling distribution of x.\nthe standard deviation of values.\nthe parameter.\nthe probability that x is obtained.

ch 15 an srs of 25 recent birth records at the local hospital was selected. in the sample, the average birth weight was $\bar{x}=119.6$ ounces. suppose the standard deviation is known to be $sigma = 6.5$ ounces. assume that in the population of all babies born in this hospital, the birth weights follow a normal distribution, with mean $mu$. the standard deviation of the sampling distribution of the mean is\n6.52 ounces.\n1.30 ounces.\n0.02 ounce.\n0.38 ounce.\n\nquestion 14\nch 15 suppose youre in a class of 35 students. the instructor takes a simple random sample of seven students and observes their heights. imagine all of the different samples possible. let x denote the tallest height in your sample. the distribution of all values taken by x in all possible samples of seven students selected from the 35 students in your class is\nthe sampling distribution of x.\nthe standard deviation of values.\nthe parameter.\nthe probability that x is obtained.

Answer

Explanation:

Step1: Recall the formula for standard deviation of the sampling - distribution of the mean

The formula for the standard deviation of the sampling - distribution of the mean (also known as the standard error) is $\sigma_{\bar{x}}=\frac{\sigma}{\sqrt{n}}$, where $\sigma$ is the population standard deviation and $n$ is the sample size.

Step2: Identify the values of $\sigma$ and $n$

We are given that $\sigma = 6.5$ ounces and $n = 25$.

Step3: Calculate the standard deviation of the sampling - distribution of the mean

Substitute the values into the formula: $\sigma_{\bar{x}}=\frac{6.5}{\sqrt{25}}=\frac{6.5}{5}=1.3$ ounces.

For the second question: The distribution of all values taken by a statistic (in this case, $X$ which is the tallest height in the sample) in all possible samples of a given size from a population is called the sampling distribution of that statistic.

Answer:

Question 13: 1.30 ounces Question 14: the sampling distribution of X