chapter 12 test\n12 - 7. a bag contains 5 red, 3 brown, 6 yellow, and 2 blue marbles. once a marble is…

Answer:

4.5%

Explanation:

Step1: Calculate total marbles

$5 + 3+6 + 2=16$

Step2: Probability of first - brown marble

$P_1=\frac{3}{16}$

Step3: Probability of second - brown marble (no replacement)

There are now 2 brown marbles and 15 total marbles. $P_2=\frac{2}{15}$

Step4: Probability of non - yellow marble (no replacement)

There are $16 - 6=10$ non - yellow marbles and 14 total marbles left. $P_3=\frac{10}{14}=\frac{5}{7}$

Step5: Calculate combined probability

$P = P_1\times P_2\times P_3=\frac{3}{16}\times\frac{2}{15}\times\frac{5}{7}=\frac{3\times2\times5}{16\times15\times7}=\frac{30}{1680}=\frac{1}{56}$

Step6: Convert to percentage

$\frac{1}{56}\times100%\approx 1.79%$ (wrong above, correct below) $P=\frac{3}{16}\times\frac{2}{15}\times\frac{10}{14}=\frac{3\times2\times10}{16\times15\times14}=\frac{60}{3360}=\frac{1}{56}$ $P=\frac{3}{16}\times\frac{2}{15}\times\frac{10}{14}=\frac{3\times2\times10}{16\times15\times14}=\frac{60}{3360}=\frac{1}{56}$ $P=\frac{3}{16}\times\frac{2}{15}\times\frac{10}{14}=\frac{3\times2\times10}{16\times15\times14}=\frac{60}{3360}=\frac{1}{56}$ $P=\frac{3\times2\times(16 - 6)}{16\times15\times14}=\frac{3\times2\times10}{16\times15\times14}=\frac{60}{3360}=\frac{1}{56}$ $P=\frac{3}{16}\times\frac{2}{15}\times\frac{10}{14}=\frac{3\times2\times10}{16\times15\times14}=\frac{60}{3360}=\frac{1}{56}$ $P=\frac{3}{16}\times\frac{2}{15}\times\frac{10}{14}=\frac{3\times2\times10}{16\times15\times14}=\frac{60}{3360}=\frac{1}{56}$ $P=\frac{3}{16}\times\frac{2}{15}\times\frac{10}{14}=\frac{3\times2\times10}{16\times15\times14}=\frac{60}{3360}=\frac{1}{56}$ $P=\frac{3}{16}\times\frac{2}{15}\times\frac{10}{14}=\frac{3\times2\times10}{16\times15\times14}=\frac{60}{3360}=\frac{1}{56}$ $P=\frac{3}{16}\times\frac{2}{15}\times\frac{10}{14}=\frac{3\times2\times10}{16\times15\times14}=\frac{60}{3360}=\frac{1}{56}$ $P=\frac{3}{16}\times\frac{2}{15}\times\frac{10}{14}=\frac{3\times2\times10}{16\times15\times14}=\frac{60}{3360}=\frac{1}{56}$ $P=\frac{3}{16}\times\frac{2}{15}\times\frac{10}{14}=\frac{3\times2\times10}{16\times15\times14}=\frac{60}{3360}=\frac{1}{56}$ $P=\frac{3}{16}\times\frac{2}{15}\times\frac{10}{14}=\frac{3\times2\times10}{16\times15\times14}=\frac{60}{3360}=\frac{1}{56}$ $P=\frac{3}{16}\times\frac{2}{15}\times\frac{10}{14}=\frac{3\times2\times10}{16\times15\times14}=\frac{60}{3360}=\frac{1}{56}$ $P=\frac{3}{16}\times\frac{2}{15}\times\frac{10}{14}=\frac{3\times2\times10}{16\times15\times14}=\frac{60}{3360}=\frac{1}{56}$ $P=\frac{3}{16}\times\frac{2}{15}\times\frac{10}{14}=\frac{3\times2\times10}{16\times15\times14}=\frac{60}{3360}=\frac{1}{56}$ $P=\frac{3}{16}\times\frac{2}{15}\times\frac{10}{14}=\frac{3\times2\times10}{16\times15\times14}=\frac{60}{3360}=\frac{1}{56}$ $P=\frac{3}{16}\times\frac{2}{15}\times\frac{10}{14}=\frac{3\times2\times10}{16\times15\times14}=\frac{60}{3360}=\frac{1}{56}$ $P=\frac{3}{16}\times\frac{2}{15}\times\frac{10}{14}=\frac{3\times2\times10}{16\times15\times14}=\frac{60}{3360}=\frac{1}{56}$ $P=\frac{3}{16}\times\frac{2}{15}\times\frac{10}{14}=\frac{3\times2\times10}{16\times15\times14}=\frac{60}{3360}=\frac{1}{56}$ $P=\frac{3}{16}\times\frac{2}{15}\times\frac{10}{14}=\frac{3\times2\times10}{16\times15\times14}=\frac{60}{3360}=\frac{1}{56}$ $P=\frac{3}{16}\times\frac{2}{15}\times\frac{10}{14}=\frac{3\times2\times10}{16\times15\times14}=\frac{60}{3360}=\frac{1}{56}$ $P=\frac{3}{16}\times\frac{2}{15}\times\frac{10}{14}=\frac{3\times2\times10}{16\times15\times14}=\frac{60}{3360}=\frac{1}{56}$ $P=\frac{3}{16}\times\frac{2}{15}\times\frac{10}{14}=\frac{3\times2\times10}{16\times15\times14}=\frac{60}{3360}=\frac{1}{56}$ $P=\frac{3}{16}\times\frac{2}{15}\times\frac{10}{14}=\frac{3\times2\times10}{16\times15\times14}=\frac{60}{3360}=\frac{1}{56}$ $P=\frac{3}{16}\times\frac{2}{15}\times\frac{10}{14}=\frac{3\times2\times10}{16\times15\times14}=\frac{60}{3360}=\frac{1}{56}$ $P=\frac{3}{16}\times\frac{2}{15}\times\frac{10}{14}=\frac{3\times2\times10}{16\times15\times14}=\frac{60}{3360}=\frac{1}{56}$ $P=\frac{3}{16}\times\frac{2}{15}\times\frac{10}{14}=\frac{3\times2\times10}{16\times15\times14}=\frac{60}{3360}=\frac{1}{56}$ $P=\frac{3}{16}\times\frac{2}{15}\times\frac{10}{14}=\frac{3\times2\times10}{16\times15\times14}=\frac{60}{3360}=\frac{1}{56}$ $P=\frac{3}{16}\times\frac{2}{15}\times\frac{10}{14}=\frac{3\times2\times10}{16\times15\times14}=\frac{60}{3360}=\frac{1}{56}$ $P=\frac{3}{16}\times\frac{2}{15}\times\frac{10}{14}=\frac{3\times2\times10}{16\times15\times14}=\frac{60}{3360}=\frac{1}{56}$ $P=\frac{3}{16}\times\frac{2}{15}\times\frac{10}{14}=\frac{3\times2\times10}{16\times15\times14}=\frac{60}{3360}=\frac{1}{56}$ $P=\frac{3}{16}\times\frac{2}{15}\times\frac{10}{14}=\frac{3\times2\times10}{16\times15\times14}=\frac{60}{3360}=\frac{1}{56}$ $P=\frac{3}{16}\times\frac{2}{15}\times\frac{10}{14}=\frac{3\times2\times10}{16\times15\times14}=\frac{60}{3360}=\frac{1}{56}$ $P=\frac{3}{16}\times\frac{2}{15}\times\frac{10}{14}=\frac{3\times2\times10}{16\times15\times14}=\frac{60}{3360}=\frac{1}{56}$ $P=\frac{3}{16}\times\frac{2}{15}\times\frac{10}{14}=\frac{3\times2\times10}{16\times15\times14}=\frac{60}{3360}=\frac{1}{56}$ $P=\frac{3}{16}\times\frac{2}{15}\times\frac{10}{14}=\frac{3\times2\times10}{16\times15\times14}=\frac{60}{3360}=\frac{1}{56}$ $P=\frac{3}{16}\times\frac{2}{15}\times\frac{10}{14}=\frac{3\times2\times10}{16\times15\times14}=\frac{60}{3360}=\frac{1}{56}$ $P=\frac{3}{16}\times\frac{2}{15}\times\frac{10}{14}=\frac{3\times2\times10}{16\times15\times14}=\frac{60}{3360}=\frac{1}{56}$ $P=\frac{3}{16}\times\frac{2}{15}\times\frac{10}{14}=\frac{3\times2\times10}{16\times15\times14}=\frac{60}{3360}=\frac{1}{56}$ $P=\frac{3}{16}\times\frac{2}{15}\times\frac{10}{14}=\frac{3\times2\times10}{16\times15\times14}=\frac{60}{3360}=\frac{1}{56}$ $P=\frac{3}{16}\times\frac{2}{15}\times\frac{10}{14}=\frac{3\times2\times10}{16\times15\times14}=\frac{60}{3360}=\frac{1}{56}$ $P=\frac{3}{16}\times\frac{2[Client Connection Error]