chapter 4.3 homework\nscore: 29/42 answered: 24/33\nquestion 25\n0/1 pt 2 99 details\n4.3 conditional…

chapter 4.3 homework\nscore: 29/42 answered: 24/33\nquestion 25\n0/1 pt 2 99 details\n4.3 conditional probability. two - way conditional table.\ngiving a test to a group of students, the grades and gender are summarized below\n| | a | b | c | total |\n|--|--|--|--|--|\n| male | 6 | 11 | 17 | 34 |\n| female | 7 | 18 | 5 | 30 |\n| total | 13 | 29 | 22 | 64 |\nif one student is chosen at random, find the probability that the student was female or got an \c\. type as a fraction.\nquestion help: video message instructor

chapter 4.3 homework\nscore: 29/42 answered: 24/33\nquestion 25\n0/1 pt 2 99 details\n4.3 conditional probability. two - way conditional table.\ngiving a test to a group of students, the grades and gender are summarized below\n| | a | b | c | total |\n|--|--|--|--|--|\n| male | 6 | 11 | 17 | 34 |\n| female | 7 | 18 | 5 | 30 |\n| total | 13 | 29 | 22 | 64 |\nif one student is chosen at random, find the probability that the student was female or got an \c\. type as a fraction.\nquestion help: video message instructor

Answer

Explanation:

Step1: Recall probability formula

The formula for $P(A\cup B)=P(A)+P(B)-P(A\cap B)$. Let $A$ be the event that the student is female and $B$ be the event that the student got a 'C'.

Step2: Calculate $P(A)$

The number of female students is $30$, and the total number of students is $64$. So $P(A)=\frac{30}{64}$.

Step3: Calculate $P(B)$

The number of students who got a 'C' is $22$, so $P(B)=\frac{22}{64}$.

Step4: Calculate $P(A\cap B)$

The number of female students who got a 'C' is $5$, so $P(A\cap B)=\frac{5}{64}$.

Step5: Calculate $P(A\cup B)$

$P(A\cup B)=\frac{30}{64}+\frac{22}{64}-\frac{5}{64}=\frac{30 + 22- 5}{64}=\frac{47}{64}$.

Answer:

$\frac{47}{64}$