chapter 3: 3.3 two basic rules of probability homework due: sun sep 14, 2025 11:59pm attempt 1 in progress…

chapter 3: 3.3 two basic rules of probability homework due: sun sep 14, 2025 11:59pm attempt 1 in progress next up: submit assignment details no additional details were added for this assignment. chapter 3: 3.3 two basic rules of probability homework score: 0/14 answered: 0/8 question 1 the table summarizes results from 983 pedestrian deaths that were caused by automobile accidents. \n|driver intoxicated?|pedestrian intoxicated?| | | |yes|no| |yes|52|67| |no|215|649| if one of the pedestrian deaths is randomly selected, find the probability that the driver was not intoxicated but the pedestrian was. please enter a decimal to 4 places. probability =

chapter 3: 3.3 two basic rules of probability homework due: sun sep 14, 2025 11:59pm attempt 1 in progress next up: submit assignment details no additional details were added for this assignment. chapter 3: 3.3 two basic rules of probability homework score: 0/14 answered: 0/8 question 1 the table summarizes results from 983 pedestrian deaths that were caused by automobile accidents. \n|driver intoxicated?|pedestrian intoxicated?| | | |yes|no| |yes|52|67| |no|215|649| if one of the pedestrian deaths is randomly selected, find the probability that the driver was not intoxicated but the pedestrian was. please enter a decimal to 4 places. probability =

Answer

Explanation:

Step1: Identify relevant values

The number of cases where driver was not intoxicated but pedestrian was is 215. The total number of pedestrian - deaths is 983.

Step2: Calculate probability

The probability formula is $P=\frac{\text{Number of favorable outcomes}}{\text{Total number of outcomes}}$. So, $P = \frac{215}{983}$. $P\approx0.2187$

Answer:

0.2187