a citys annual rainfall totals are normally distributed, and the probability that the city gets more than…

a citys annual rainfall totals are normally distributed, and the probability that the city gets more than 43.2 inches of rain in a year is given by p(z≥1.5)=0.0668. if the standard deviation of the citys yearly rainfall totals is 1.8 inches, what is the citys mean annual rainfall?\n40.5 inches\n41.4 inches\n45.0 inches\n45.9 inches
Answer
Answer:
40.5 inches
Explanation:
Step1: Recall z - score formula
The z - score formula is $z=\frac{x-\mu}{\sigma}$, where $x$ is the value from the data set, $\mu$ is the mean, and $\sigma$ is the standard deviation. We know that $z = 1.5$, $x=43.2$ inches, and $\sigma = 1.8$ inches.
Step2: Rearrange the z - score formula for the mean
From $z=\frac{x - \mu}{\sigma}$, we can solve for $\mu$. First, multiply both sides by $\sigma$: $z\sigma=x-\mu$. Then, rearrange to get $\mu=x - z\sigma$.
Step3: Substitute the known values
Substitute $x = 43.2$, $z = 1.5$, and $\sigma=1.8$ into the formula $\mu=x - z\sigma$. $\mu=43.2-1.5\times1.8$. First, calculate $1.5\times1.8 = 2.7$. Then, $\mu=43.2 - 2.7=40.5$ inches.