a clothing item is randomly drawn from a box with 15 small shirts, 5 large shirts, 19 small pants, and 11…

a clothing item is randomly drawn from a box with 15 small shirts, 5 large shirts, 19 small pants, and 11 medium pants.\nevent a: small\nevent b: pants\np(a or b) =?\nhint: p(a or b) = p(a) + p(b) - p(a and b)\nround your answer to the nearest hundredth.

a clothing item is randomly drawn from a box with 15 small shirts, 5 large shirts, 19 small pants, and 11 medium pants.\nevent a: small\nevent b: pants\np(a or b) =?\nhint: p(a or b) = p(a) + p(b) - p(a and b)\nround your answer to the nearest hundredth.

Answer

Explanation:

Step1: Calculate total number of clothing items

$15 + 5+19 + 11=50$

Step2: Calculate $P(A)$

Number of small - sized items is $15 + 19=34$. So $P(A)=\frac{34}{50}$.

Step3: Calculate $P(B)$

Number of pants is $19 + 11=30$. So $P(B)=\frac{30}{50}$.

Step4: Calculate $P(A\ and\ B)$

Number of small - sized pants is $19$. So $P(A\ and\ B)=\frac{19}{50}$.

Step5: Calculate $P(A\ or\ B)$

Using the formula $P(A\ or\ B)=P(A)+P(B)-P(A\ and\ B)$, we have $P(A\ or\ B)=\frac{34}{50}+\frac{30}{50}-\frac{19}{50}=\frac{34 + 30-19}{50}=\frac{45}{50}=0.90$

Answer:

$0.90$