college tuition: the mean annual tuition and fees for a sample of 22 private colleges in california was…

college tuition: the mean annual tuition and fees for a sample of 22 private colleges in california was $38,750 with a standard deviation of $7200. a dot - plot shows that it is reasonable to assume that the population is approximately normal. can you conclude that the mean tuition and fees for private institutions in california differs from $35,000? use the $alpha = 0.01$ level of significance and the $p$-value method with the ti - 84 plus calculator.\npart: 0 / 5\npart 1 of 5\n(a) state the appropriate null and alternate hypotheses.\n$h_0$: \n$h_1$: \nthis hypothesis test is a (choose one) test.

college tuition: the mean annual tuition and fees for a sample of 22 private colleges in california was $38,750 with a standard deviation of $7200. a dot - plot shows that it is reasonable to assume that the population is approximately normal. can you conclude that the mean tuition and fees for private institutions in california differs from $35,000? use the $alpha = 0.01$ level of significance and the $p$-value method with the ti - 84 plus calculator.\npart: 0 / 5\npart 1 of 5\n(a) state the appropriate null and alternate hypotheses.\n$h_0$: \n$h_1$: \nthis hypothesis test is a (choose one) test.

Answer

Explanation:

Step1: Define null and alternative hypotheses

The null hypothesis $H_0$ is a statement of no - effect or no difference. We want to test if the mean tuition and fees $\mu$ differs from $$35000$. So, $H_0:\mu = 35000$. The alternative hypothesis $H_1$ is what we are trying to find evidence for. Since we are testing if the mean differs (a two - tailed test), $H_1:\mu\neq35000$.

Step2: Determine the type of test

When the alternative hypothesis has $\neq$, it is a two - tailed test.

Answer:

$H_0:\mu = 35000$ $H_1:\mu\neq35000$ This hypothesis test is a two - tailed test.