consider the following sample data, which represent weights walnuts in grams: { 10.6, 10.9, 11.6, 11.7…

consider the following sample data, which represent weights walnuts in grams: { 10.6, 10.9, 11.6, 11.7, 12.9, 13.5, 13.5, 14, 14, 14, 14.4, 14.6, 14.9, 15.4, 16.3, 16.6, 17.2, 17.2, 17.8 , 18.5 }. first, give the mean of the data set. part 2 of 6 next, give the median of the data set. part 3 of 6 now give the mode of the data set. if there is more than one, write them in order, separated by commas.

consider the following sample data, which represent weights walnuts in grams: { 10.6, 10.9, 11.6, 11.7, 12.9, 13.5, 13.5, 14, 14, 14, 14.4, 14.6, 14.9, 15.4, 16.3, 16.6, 17.2, 17.2, 17.8 , 18.5 }. first, give the mean of the data set. part 2 of 6 next, give the median of the data set. part 3 of 6 now give the mode of the data set. if there is more than one, write them in order, separated by commas.

Answer

Explanation:

Step1: Recall the formula for the mean

The mean $\bar{x}=\frac{\sum_{i = 1}^{n}x_{i}}{n}$, where $x_{i}$ are the data - points and $n$ is the number of data - points. Here, $n = 20$. $\sum_{i=1}^{20}x_{i}=10.6 + 10.9+11.6+11.7+12.9+13.5+13.5+14+14+14+14.4+14.6+14.9+15.4+16.3+16.6+17.2+17.2+17.8+18.5=283.3$ $\bar{x}=\frac{283.3}{20}=14.165$

Step2: Recall the formula for the median

Since $n = 20$ (an even number), the median is the average of the $\frac{n}{2}$ - th and $(\frac{n}{2}+1)$ - th ordered data - points. The data is already ordered. $\frac{n}{2}=10$ and $\frac{n}{2}+1 = 11$. The 10 - th value is 14 and the 11 - th value is 14.4. Median $=\frac{14 + 14.4}{2}=14.2$

Step3: Recall the formula for the mode

The mode is the data - point(s) that occur(s) most frequently. In the data set, 14 occurs 3 times and 13.5 and 17.2 each occur 2 times, and all other values occur only once. So the mode is 14.

Answer:

Part 1: 14.165 Part 2: 14.2 Part 3: 14