to control pollination, pollen - producing flowers are often removed from the top of corn in a process…

to control pollination, pollen - producing flowers are often removed from the top of corn in a process called detasseling. the hourly rates for detasselers in iowa are roughly normally distributed, with a mean of $12/hr and a standard deviation of $2/hr.\nwhat are the z - scores for a detasseler making $13 and $17 an hour?\n$z_{13}=0.9,z_{17}=1.25$\n$z_{13}=0.5,z_{17}=1.25$\n$z_{13}=0.5,z_{17}=2.5$

to control pollination, pollen - producing flowers are often removed from the top of corn in a process called detasseling. the hourly rates for detasselers in iowa are roughly normally distributed, with a mean of $12/hr and a standard deviation of $2/hr.\nwhat are the z - scores for a detasseler making $13 and $17 an hour?\n$z_{13}=0.9,z_{17}=1.25$\n$z_{13}=0.5,z_{17}=1.25$\n$z_{13}=0.5,z_{17}=2.5$

Answer

Explanation:

Step1: Recall z - score formula

The z - score formula is $z=\frac{x-\mu}{\sigma}$, where $x$ is the value, $\mu$ is the mean, and $\sigma$ is the standard deviation. Given $\mu = 12$ and $\sigma=2$.

Step2: Calculate $z_{13}$

Substitute $x = 13$, $\mu = 12$, and $\sigma = 2$ into the formula: $z_{13}=\frac{13 - 12}{2}=\frac{1}{2}=0.5$.

Step3: Calculate $z_{17}$

Substitute $x = 17$, $\mu = 12$, and $\sigma = 2$ into the formula: $z_{17}=\frac{17 - 12}{2}=\frac{5}{2}=2.5$.

Answer:

$z_{13}=0.5,z_{17}=2.5$