7. of the customers at a sandwich shop, 19% choose ham and 31% choose white bread. if 9% of customers choose…

7. of the customers at a sandwich shop, 19% choose ham and 31% choose white bread. if 9% of customers choose ham with white bread, what is the probability that the next customer will choose either ham or white bread?\na. 32%\nb. 41%\nc. 50%\nd. 59%

7. of the customers at a sandwich shop, 19% choose ham and 31% choose white bread. if 9% of customers choose ham with white bread, what is the probability that the next customer will choose either ham or white bread?\na. 32%\nb. 41%\nc. 50%\nd. 59%

Answer

Explanation:

Step1: Recall the formula for the probability of the union of two events

The formula for $P(A\cup B)$ is $P(A)+P(B)-P(A\cap B)$. Let event $A$ be choosing ham and event $B$ be choosing white - bread.

Step2: Identify the given probabilities

We are given that $P(A) = 19%=0.19$, $P(B)=31% = 0.31$, and $P(A\cap B)=9%=0.09$.

Step3: Calculate $P(A\cup B)$

Substitute the values into the formula: $P(A\cup B)=P(A)+P(B)-P(A\cap B)=0.19 + 0.31-0.09$. $P(A\cup B)=0.41$ or $41%$.

Answer:

B. 41%