the daily high temperatures in a vacation resort city are approximately normal, with a mean temperature of…

the daily high temperatures in a vacation resort city are approximately normal, with a mean temperature of 75 degrees fahrenheit and a standard deviation of 6 degrees. if a weather forecast predicts the high temperature will be at most 68 degrees, the city provides fewer lifeguards for the city beaches. on what percentage of days will fewer lifeguards be provided? find the z - table here. 4.36% 12.10% 87.90% 95.64%

the daily high temperatures in a vacation resort city are approximately normal, with a mean temperature of 75 degrees fahrenheit and a standard deviation of 6 degrees. if a weather forecast predicts the high temperature will be at most 68 degrees, the city provides fewer lifeguards for the city beaches. on what percentage of days will fewer lifeguards be provided? find the z - table here. 4.36% 12.10% 87.90% 95.64%

Answer

Answer:

12.10%

Explanation:

Step1: Calculate the z - score

The z - score formula is $z=\frac{x-\mu}{\sigma}$, where $x = 68$, $\mu=75$, and $\sigma = 6$. So $z=\frac{68 - 75}{6}=\frac{-7}{6}\approx - 1.17$.

Step2: Use the z - table

Looking up the value of $z=-1.17$ in the standard normal (z -) table, the corresponding cumulative probability is approximately $0.1210$ or $12.10%$. This represents the percentage of days with a high - temperature of at most 68 degrees.