darrell wants to see how much water is wasted by his leaky faucet. he puts a 4 - gallon bucket under the…

darrell wants to see how much water is wasted by his leaky faucet. he puts a 4 - gallon bucket under the faucet. after 24 hours, the bucket is full. if the same amount of water leaks each hour, how much water will leak in 60 hours? \n| water (gallons) | 4 | |\n| ---- | ---- | ---- |\n| hours | 24 | 60 |

darrell wants to see how much water is wasted by his leaky faucet. he puts a 4 - gallon bucket under the faucet. after 24 hours, the bucket is full. if the same amount of water leaks each hour, how much water will leak in 60 hours? \n| water (gallons) | 4 | |\n| ---- | ---- | ---- |\n| hours | 24 | 60 |

Answer

Explanation:

Step1: Find the leakage rate per hour

The faucet leaks 4 gallons in 24 hours. So the rate ( r ) is ( \frac{4}{24} ) gallons per hour. Simplify ( \frac{4}{24}=\frac{1}{6} ) gallons per hour.

Step2: Calculate water leakage in 60 hours

Using the rate, the amount of water ( W ) in 60 hours is ( r\times60 ). Substitute ( r = \frac{1}{6} ), so ( W=\frac{1}{6}\times60 = 10 ) gallons. Alternatively, set up a proportion: ( \frac{4}{24}=\frac{x}{60} ), cross - multiply: ( 24x = 4\times60 ), ( 24x=240 ), then ( x = \frac{240}{24}=10 ).

Answer:

10 gallons