the data below are the frequency of cremation burials found in 17 archaeological sites. a. obtain the mean…

the data below are the frequency of cremation burials found in 17 archaeological sites. a. obtain the mean, median, and mode of these data. b. which measure of center do you think works best here? 84 60 46 49 522 34 33 285 2377 46 377 29 88 410 56 236 110 a. the mean is 270 (round to one decimal place as needed.)

the data below are the frequency of cremation burials found in 17 archaeological sites. a. obtain the mean, median, and mode of these data. b. which measure of center do you think works best here? 84 60 46 49 522 34 33 285 2377 46 377 29 88 410 56 236 110 a. the mean is 270 (round to one decimal place as needed.)

Answer

Explanation:

Step1: Calculate the sum of data

Sum = (84 + 60+46 + 49+522+34+33+285+2377+46+377+29+88+410+56+236+110) Sum = (4780)

Step2: Calculate the mean

There are (n = 17) data - points. Mean (\bar{x}=\frac{\text{Sum}}{n}=\frac{4780}{17}\approx281.2)

Step3: Arrange data in ascending order

(29,33,34,46,46,49,56,60,84,88,110,236,285,377,410,522,2377)

Step4: Calculate the median

Since (n = 17) (an odd - numbered data set), the median is the (\left(\frac{n + 1}{2}\right))-th value. (\frac{17+1}{2}=9) - th value. So the median is (84).

Step5: Calculate the mode

The mode is the value that appears most frequently. Here, (46) appears twice and other values appear only once, so the mode is (46).

Step6: Discuss the best measure of center

The data set has a large outlier ((2377)). The mean is affected by outliers. The median is a better measure of center as it is not affected by extreme values.

Answer:

a. Mean: (281.2), Median: (84), Mode: (46) b. The median works best here.