the data below are the frequency of cremation burials found in 17 archaeological sites. a. obtain the mean…

the data below are the frequency of cremation burials found in 17 archaeological sites. a. obtain the mean, median, and mode of these data. b. which measure of center do you think works best here? 80 63 46 48 528 36 35 271 2779 46 375 24 88 432 58 223 129 a. the mean is. (round to one decimal place as needed.)

the data below are the frequency of cremation burials found in 17 archaeological sites. a. obtain the mean, median, and mode of these data. b. which measure of center do you think works best here? 80 63 46 48 528 36 35 271 2779 46 375 24 88 432 58 223 129 a. the mean is. (round to one decimal place as needed.)

Answer

Explanation:

Step1: Calculate sum of data

$80 + 63+46 + 48+528+36+35+271+2779+46+375+24+88+432+58+223+129 = 5141$

Step2: Calculate the mean

The number of data points $n = 17$. Mean $\bar{x}=\frac{\sum_{i = 1}^{n}x_{i}}{n}=\frac{5141}{17}\approx302.4$

Step3: Arrange data in ascending order

$24,35,36,46,46,48,58,63,80,129,223,271,375,432,528,2779$

Step4: Find the median

Since $n = 17$ (odd), the median is the $\left(\frac{n + 1}{2}\right)$-th value. $\frac{17+ 1}{2}=9$-th value, which is $80$.

Step5: Find the mode

The mode is the value that appears most frequently. Here, $46$ appears twice and other values appear once, so the mode is $46$.

Step6: Analyze best - measure of center

The data has a large outlier ($2779$). The mean is affected by this outlier. The median is a better measure of center as it is not influenced by extreme values.

Answer:

a. Mean: $302.4$, Median: $80$, Mode: $46$ b. Median